Forklift Stability: How Much Weight to Keep from Tipping?

  • Thread starter Thread starter Ryank
  • Start date Start date
AI Thread Summary
To prevent a forklift from tipping over, it is crucial to maintain the center of gravity within the footprint of its base. The design should consider the weight distribution, especially when lifting loads like an 8 lb ball. Adjustments such as tilting the hoist tower back after picking up a load can help stabilize the forklift. Additionally, the motion of the forklift, including acceleration and deceleration, introduces g-forces that can affect stability. Applying principles like D'Alembert's can be essential in understanding how deceleration impacts tipping risk.
Ryank
Messages
4
Reaction score
0
I understand that I will probably need to give some more variables here, but I am not sure what they are. in any case, my question to you all is this: As shown in the diagram below, realistically, how much weight should be placed at the x to keep this forklift from tipping over. I am working on a robot for the FRC competition and I'm trying to find out if the physics behind our design even make sense, a 7 ft forklift holding a 42 inch diameter 8 lb ball on a 30 inch long 28 inch wide base? It just doesn't sound right.
 

Attachments

  • FIRST forklift diagram copy.jpg
    FIRST forklift diagram copy.jpg
    4.9 KB · Views: 480
Physics news on Phys.org
I can't see the picture yet. However, the process you need to follow is to ensure that the vehicle's center of gravity stays within the footprint of its tires, treads, etc...
 
Welcome to PF, Ryan.
I don't know anything about this contest, so I'll just make a suggestion that might be in violation of the rules. As Fred pointed out, you need to keep your centre of gravity over the main body. How about turning the forks around, or tilting the hoist tower back, as soon as you pick up the load?
 
One variable you will need to consider is the motion of the forklift; will it be stationary or will it drive around? If the forklift moves, then it will generate g-forces as it accelerates (decelerates). These are the forces that will cause it to tip over. I learned this the hard way.
 
In a static situation, you can simply ratio the weights and the distances, but as others said, when you start moving it, the motion comes into play.
 
russ_watters said:
In a static situation, you can simply ratio the weights and the distances, but as others said, when you start moving it, the motion comes into play.

i think you got to apply D'Alembert's principle in the case of decelleration. decellerating folklifts want to tip over toward the front. lotsa laffs when that happens.
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...
Back
Top