Form Factor - Simply take the real part?

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SUMMARY

The discussion focuses on deriving the form factor, represented by the equation ##\frac{3(sin x - x cos x)}{x^3}##, through the Fourier transform of a normalized charge density. The integral involved is ##F(q) = \int_0^R \left( \frac{\rho_0}{\frac{4}{3} \pi R^3 \rho_0} \right) e^{i \left( \frac{ q}{\hbar}\right) r} \cdot 4 \pi r^2 dr##. The user initially attempted to take only the real part of the integral, leading to an incorrect result. The correct approach involves evaluating the full integral to obtain the accurate form factor.

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  • Understanding of Fourier transforms in quantum mechanics
  • Familiarity with normalized charge density concepts
  • Knowledge of complex integration techniques
  • Proficiency in calculus, particularly integration of spherical coordinates
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Homework Statement



Show that the Form factor is ##\frac{3(sin x - x cos x)}{x^3}##.

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Homework Equations

The Attempt at a Solution


[/B]
I know that the form factor is simply the Fourier transform of the normalized charge density:
[tex]F(q) = \int \frac{\rho}{Z} e^{-i (\Delta \vec k) \cdot \vec r} d^3 r[/tex]
[tex]= \int_0^R \left( \frac{\rho_0}{\frac{4}{3} \pi R^3 \rho_0} \right) e^{i \left( \frac{ q}{\hbar}\right) r} \cdot 4 \pi r^2 dr[/tex]
[tex]= \frac{3}{R^3} \int_0^R r^2 e^{-i \left( \frac{q}{\hbar} \right) r} dr[/tex]

Do I simply take the real part of this integral? Or do I have to do some form of complex/contour integration?

I tried taking only the real part, which gave the wrong asnwer: ## F(q) = \frac{3\left(x^2 sin (x) - 2x cos(x) - 2 sin (x) \right)}{x^3}##.
 
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