Formula for resistance in parallel circuit

Click For Summary
The discussion centers on the formula for calculating equivalent resistance in parallel circuits. The original formula provided is 1/R_eq = 1/R_1 + 1/R_2 + 1/R_3 + ..., and the user seeks to express this using summation notation. The correct representation using the sigma notation is clarified as 1/R_eq = Σ (1/R_i) from i=1 to n, where n represents the total number of resistors and i serves as a counter. This correction emphasizes the proper use of summation in the context of parallel resistance calculations.
DB
Messages
501
Reaction score
0
My science teacher gave me this formula for resistance in parallel circuit.
\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+...

Thats exactly how he wrote it.
I would like this using the summation sigma

\frac{1}{R_{eq}}=\sum_{R=\frac{1}{R_n}}^n

Is that right? I am sure it's not lol...
 
Physics news on Phys.org
DB said:
My science teacher gave me this formula for resistance in parallel circuit.
\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+...

Thats exactly how he wrote it.
I would like this using the summation sigma

\frac{1}{R_{eq}}=\sum_{R=\frac{1}{R_n}}^n

Is that right? I am sure it's not lol...

Not quite. You should write it as

\frac{1}{R_{eq}}=\sum_{i=1}}^n \frac{1}{R_i}

Zz.
 
\frac{1}{R_{eq}}=\sum_{i=1}^n \frac{1}{R_i}

Where n is the number of resistors and i is just a dummy letter (a counter).
 

Similar threads

Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
10
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
9
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 13 ·
Replies
13
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K