Formula of shortest distance between two skewed lines

Click For Summary

Homework Help Overview

The discussion revolves around understanding the formula for the shortest distance between two skewed lines, specifically addressing a highlighted part of a problem statement that involves vector relationships and angles.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the validity of a specific formula related to the lengths of vectors and the cosine of an angle. There is confusion about the interpretation of the highlighted text and its implications for the problem.

Discussion Status

The discussion is active, with participants attempting to clarify the statements made in the problem. Some are referencing specific parts of the problem statement to support their points, while others are challenging the interpretations presented.

Contextual Notes

There is mention of a guideline regarding the posting of images, indicating that the original poster may have included images that could hinder the discussion. This suggests a need for clearer textual representation of the problem.

gxc9800
Messages
18
Reaction score
0

Homework Statement


kindly refer to the yellow highlighted part,
why is
IE4YzJD.jpg
but not
euFPWN9.jpg
?

Homework Equations

The Attempt at a Solution

 

Attachments

  • IMG_20141011_164815[1].jpg
    IMG_20141011_164815[1].jpg
    59.9 KB · Views: 1,712
Physics news on Phys.org
? The "yellowed part" says precisely the second: |AC|= |AB| cos(\theta)
 
  • Like
Likes   Reactions: gxc9800
HallsofIvy said:
? The "yellowed part" says precisely the second: |AC|= |AB| cos(\theta)
please refer to the lower part , it states that |AB|= |AB| cos(\theta)... after eliminate |vector b1 x vector b2|
 
No, there is nowhere, in what you posted, that says that.
 
From https://www.physicsforums.com/threads/guidelines-for-students-and-helpers.686783/
5. Do not simply post images of the problem statement or your work. While posting images may be convenient for you, it's actually one of the most effective ways of getting your request for help ignored. Images are often too big, too small, rotated, upside down, out of focus, dimly lit, or of otherwise poor quality, and your handwriting probably isn't as easy to read as you think it is. Images are a hindrance to the helpers as portions of the problem statement or your work can't easily be quoted. Using images also doesn't qualify as filling out the homework template, so your post may be deleted.
 
gxc9800 said:
please refer to the lower part , it states that |AB|= |AB| cos(\theta)... after eliminate |vector b1 x vector b2|
At the bottom of the third image you have |AC| = |AB|cos(##\theta##)
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
6
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K