Forward vs Reverse Reaction (both endo/exo thermic)

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Both the forward and reverse reactions cannot be simultaneously exothermic or endothermic due to the principle of energy conservation. Enthalpy (H) is a state function, meaning it is independent of the process path taken. The enthalpy change in any reaction is defined by the equation H_final - H_initial = ΔH. Therefore, if a forward reaction has a negative enthalpy change (exothermic), the reverse reaction will have a positive change of equal magnitude. This relationship can be expressed as H_forward = -H_reverse.
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Can both the forward and reverse reaction be endothermic or exothermic? Or must they ALWAYS be inverse one another?

Thanks
 
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What about energy conservation?
 
They cannot both be exothermic or endothermic. Enthalpy (H) is a state function. This means that the enthalpy of a system is completely independent of how one arrived at that system. It's like mass. It follows from this that the enthalpy change in any process is expressed by:

H_{final}-H_{initial} = \Delta\ H

for all processes. So if the forward process has a negative change in enthalpy (exothermic), the reverse process will have a positive change in enthalpy of equal magnitude. For a reverse reaction, you just switch the "final" and "initial" states, which amounts to multiplying the left by negative one. So this equation relates forward and reverse processes:

H_{for}= -H_{rev}

EDIT:
Sorry I can't get LaTex to work right, I'm new to this.
 
Last edited:
horsecandy911 said:
They cannot both be exothermic or endothermic. Enthalpy (H) is a state function. This means that the enthalpy of a system is completely independent of how one arrived at that system. It's like mass. It follows from this that the enthalpy change in any process is expressed by:

H_{final}-H_{initial} = \Delta\ H

for all processes. So if the forward process has a negative change in enthalpy (exothermic), the reverse process will have a positive change in enthalpy of equal magnitude. For a reverse reaction, you just switch the "final" and "initial" states, which amounts to multiplying the left by negative one. So this equation relates forward and reverse processes:

H_{for}= -H_{rev}

Good answer on this. I appreciate it. Thanks!
 
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