Four 100 kg people are holding a 1200 kg inflated balloon

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In the scenario, four individuals each weighing 100 kg are holding a 1200 kg balloon, and when three let go, the balloon accelerates upward at 2 m/s². To determine the tension in the rope held by the last person, Newton's second law is applied, considering both the gravitational force and the tension. The total force acting on the person is the difference between the tension and their weight, leading to the equation T - mg = ma. A diagram illustrating the forces can clarify the relationship between tension, weight, and acceleration. Understanding these dynamics is crucial for accurately calculating the tension in the rope.
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four 100 kg people are holding a 1200 kg inflated balloon by means of four ropes. three people let go and the balloon accelerates upward at 2 m/ s/s. what is the tension in the rope the last person is holding?
 
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What are your ideas on this?
 
t=mg?
 
These are the 2 forces on the person, but if they were equal then the person would have an acceleration of zero.

Apply Newton's second law to the person.
 
ma=mg where a = 2 so m(a-g)=0 so 800 but I know it's actually a+g so 1200 why?
 
ma = mg is not correct.

Newton 2 says that the total force on the person = ma
You've written the total force as just mg. You need to include the tension in here as well.

Just draw a quick diagram showing the forces on the person and the direction of the acceleration and then apply Newton 2, ( and be careful with the signs ).
 
oh! thank you very much
 
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