Understanding Fourier Coefficients for Step Functions: Homework Help

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Homework Statement



f(t) = 1 0<=t<T/2
-1 T/2 <=t<=T

ie. step function.frequency w_0 = 2pi/T

Homework Equations


The Attempt at a Solution



What's the definition for the Fourier coefficients a_n and b_n again? Not the one in wikipedia.
 
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Show us the work you have done on this. There are defining integrals for these coefficients, so set them up and try evaluating them.
 
<br /> <br /> a_n = \frac{1}{\pi} \int_0^{T/2} 1*cos(nt) dt +\frac{1}{\pi} \int_{T/2}^{T} (-1)*cos(nt) dt <br />

<br /> <br /> b_n = \frac{1}{\pi} \int_0^{T/2} 1*sin(nt) dt +\frac{1}{\pi} \int_{T/2}^{T} (-1)*sin(nt) dt <br />

I think the normalization factor is incorrect, which is why i asked for the definition, I think it was 2/L where L is the length of the interval - i can't remember.
 
If you can't remember, do you have a book?
 
No, that's why I asked.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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