Fourier Series Convergence at the Origin

robertjford80
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Homework Statement



Screenshot2012-06-17at15610AM.png


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The Attempt at a Solution



Obviously brackets mean something other than parentheses because .5[0 + 0] ≠ .5
 
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The brackets mean the same thing as parentheses...

I was unable to "Dirichlet's theorem" on the web, except as it applies to number theory and prime numbers. In Kreyszig's Advanced Engineering Mathematics, 3rd Ed., there is a theorem (identified only as Theorem 1) in the section titled "Fourier Series. Euler Formulas," and I believe that's the one you're mentioning.

If a periodic function f(x) with period ##2\pi## is piecewise continuous in the interval ##-\pi \leq x \leq \pi## and has a left-and right-hand derivative at each point of that interval, then the corresponding Fourier series (7) [with coefficients (6)] is convergent. Its sum is f(x), except at a point x0 at which f(x) is discontinuous and the sum of the series is the average of the left- and right-hand limits of f(x) at x0.
The numbers in parentheses are, respectively, the usual definition of a Fourier series, and the formulas for the coefficients of the series.

The theorem is talking more about the function represented by the Fourier series, and not so much about the function the series represents. At most points, the two are identical, but at discontinuities, they are different.

The theorem doesn't say that f(##-\pi/2##) = 1/2. It says that the value of the series at x = ##-\pi/2## is 1/2.
 
robertjford80 said:


Screenshot2012-06-17at15615AM.png




The Attempt at a Solution



Obviously brackets mean something other than parentheses because .5[0 + 0] ≠ .5


That's just a typo. It should read$$\frac 1 2[f(0^+)+f(0^-) =\frac 1 2 [0+1]=\frac 1 2$$and it isn't f(0); it is the value of the FS at 0.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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