Fourier transform of signum function*exponential

quebecois22
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Homework Statement



Using properties of the Fourier transform, calculate the Fourier transform of: sgn(x)*e^(-a*abs(x-2))

Homework Equations



FT(f(x))= integral from -∞ to +∞ of f(x)*e^(-iwx) dx

The Attempt at a Solution



I've realized that with the signum function, the boundaries of the integral can be reduced to: integral from 0 to 4 of e^(-a*abs(x-2))*e^(-iwx) dx from 0 to 4. However I'm guessing that I just can't use the properties and theorems related to Fourier transforms as the integral does not have the same boundaries as the original... Maybe I just souldn't have changed the integral...Any help?

Sorry for not using latex I really don't understand it =/
 

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What was your reasoning that you could change the limits to 0 and 4?
 
The function from -∞ to 0 is the opposite of the function from 4 to ∞ so they cancel out. Can I do that?
 
That's true for f(x) but not for f(x)e-iωx. The exponential messes things up.
 
Ahh indeed :(... How should I approach it then?
 
I suggest using the convolution theorem. Or just grind it out — it doesn't look like there's anything tricky going on.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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