Fourier Transform of x(t) = ae^(bt)*u(-t)

AI Thread Summary
The discussion focuses on calculating the Fourier Transform of the function x(t) = ae^(bt)*u(-t). The user correctly sets up the integral for the Fourier Transform, resulting in F[x(t)] = a/(b-jw). A key point raised is the role of the unit step function u(-t), which is not included in the Fourier Transform calculation because it defines the limits of integration. The unit step function u(-t) indicates that the function is only defined for negative time values. Overall, the user's approach to the problem is validated, with clarification provided on the significance of u(-t).
Larrytsai
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Hey I am trying to figure out this easy problem, and I don't know if I am doing this properly or not here's the questions & the work.

x(t) = ae^(bt)*u(-t)

F[x(t)] = a*integral[(e^bt)*e^(-jwt)*dt] upper bound = 0 lower bound = -infinity
= [a*e^(t(b-jw))] / (b-jw)
= a/(b-jw)
 
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What's u(-t), and why is it not part of the Fourier transform? Otherwise, your work is correct.
 
u(-t) is the unit step function with a time reversal.
 

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