Franck hertz experiment problem

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SUMMARY

The discussion centers on calculating the potential difference required for electrons to emit the first line of the Balmer series in hydrogen. The correct transition for this emission occurs from n = 3 to n = 2, leading to the wavelength of 6.563 x 10-7 m and energy of 3.03 x 10-19 J. The calculated potential difference of 1.89 V is incorrect; the required potential difference is 12.1 V. The error lies in not accounting for the initial energy level that electrons must reach before transitioning to the lower energy state.

PREREQUISITES
  • Understanding of the Balmer series in hydrogen
  • Familiarity with the Rydberg formula: 1/l = R(1/ni2 - 1/nf2)
  • Knowledge of energy calculations using E = hc/l
  • Basic principles of electron acceleration and potential difference (V = E/Q)
NEXT STEPS
  • Study the Rydberg formula in detail to understand spectral lines
  • Learn about electron transitions in hydrogen and their energy implications
  • Explore the concept of potential difference in electron acceleration
  • Investigate the relationship between wavelength, frequency, and energy in quantum mechanics
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone studying atomic transitions and quantum mechanics, particularly in the context of hydrogen emissions.

cooper607
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Homework Statement



a beam of electrons bombards a sample of hydrogen. through what potential difference must the electrons have been accelerated if the first line of balmer series is to be emitted

Homework Equations



1/l=R(1/2^2-1/3^2)

E=hc/l

v=E/Q

The Attempt at a Solution



i first tried to find the wavelngth corresponding to first balmer series where i put ni=2 &nf=3.. first let me know if this interpretation is correct

then i found the wavelength l=6.563* E-7 m

according to E=3.03*E-19J

and finally V=E/Q=1.89 V

but the result has to be 12.1 V

please let me know where's the problem

regrds
 
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The first line of the Balmer series is emitted when the atom goes from n = 3 to n = 2. You found the wavelength and energy of that transition, but that's not what they asked for.

Hint: Before it can drop to a lower energy level it first must reach the higher level.
 

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