Free Body Diagram Help: Learn How to Draw It

bobmarly12345
Messages
26
Reaction score
0

Homework Statement


can anyone show me what the free body diagram of this would look like?
Thankyou
 

Attachments

  • P10001053.jpg
    P10001053.jpg
    22.6 KB · Views: 446
Physics news on Phys.org
bobmarly12345 said:

Homework Statement


can anyone show me what the free body diagram of this would look like?
Thank you
For which body do you want the Free Body Diagram? ... mass K, mass L, the pulley at N, or the junction of the cables at H
 
well the question asks me to work out the mass of K
 
There are three forces acting at H. First there is a horizontal force acting toward point G. Second, there is a vertical force due to the weight of K. Third there is a force toward point N. The magnitude of the downward force is, of course, mg. The magnitude of the force toward N is the same as the weight of the mass at L. Decompose the force toward N into its horizontal and vertical components.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top