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## Homework Statement

An object is launched upwards with a velocity of 25 m/s. At what time (or times) will the object be located twenty meters above the ground?

## Homework Equations

## The Attempt at a Solution

I started off with the following variable list:

Xo=0 Vo=25

X=0 V=0

t=? a=-9.8

Which seems very off to me.

When trying to solve I got 2.55 seconds. But is there another time where it reaches 20m?

How do you solve this?

Thanks!

[tex]x=V_0 t-\frac{1}{2}gt^2[/tex]

will help you. Remember it is going up, reaching maximum height and falling back down to the ground. So at two times it will be 20m up in the air.

Would my answers be 0.994sec and 1.557sec?