Freeboard calculations for pontoon with additional weight

AI Thread Summary
The discussion focuses on calculating the weight needed to decrease the freeboard of a concrete pontoon by 0.3m on one side, which will raise the opposite side by the same amount. The pontoon measures 114.84m x 15m x 3.4m and has an initial freeboard of 1m, with a total weight of approximately 4,134,240kg. Participants explore how the freeboard will change when the pontoon tilts, suggesting that one end will be at 0.7m and the other at 1.3m above the waterline. The challenge lies in determining the exact weight required to achieve this tilt while considering the distribution of the added weight. The conversation emphasizes the complexities of measuring freeboard in a tilted state.
Peter T
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I seem to be stuck in a rut and so I was hoping you guys could help me out with this should-be easy question.. The pontoon dimensions are (L x W x H) 114.84m X 15m X 3.4m. Made of concrete. There is about 1m of freeboard so I figured using the water displacement, the structure weights about 4,134,240kg.

What I can't seem to figure out is how much weight is needed to decrease the freeboard by 0.3m on one side which will raise the other side by 0.3m.. The picture added shows that the weight will be added 5.96m from one side of the pontoon (assume that added weight is evenly distributed throughout).

Question seems like it would have a simple answer..

Thanks!
 

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If you tip the pontoon, how will you then define freeboard? Where will you measure it?
 
Dr.D said:
If you tip the pontoon, how will you then define freeboard? Where will you measure it?

I assume the freeboard will change from the initial 1m to 0.7m on one end and 1.3m on the other end of the pontoon. The freeboard in this example is just the water surface to the deck of the pontoon.. Hopefully I've answered your question
 
** the pontoon would be tilting on its longitudinal axis. So one end up as 0.7m above waterline and the other end of the pontoon will be 1.3m above waterline
 
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