Freight Wagons Collision: Calculating Speed, Acceleration & Force

AI Thread Summary
An empty freight wagon of mass 10,000 kg collides with a stationary loaded wagon of mass 15,000 kg, and the discussion focuses on calculating their joint speed post-collision, acceleration during the collision, and the forces involved. The conservation of momentum is the key principle applied, where the initial momentum of the moving wagon equals the combined momentum after the collision. Participants clarify the definitions of variables in the momentum equation and confirm that the collision is inelastic, meaning both wagons will move together after impact. The conversation emphasizes the importance of substituting the correct values into the momentum equation to find the final velocity. Overall, the discussion serves as a foundational exploration of collision physics for beginners.
ollieman
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Homework Statement



An empty freight wagon of mass 10000kg rolls at 2.0 ms-1 along a level track and collides with a loaded wagon with a mass of 15000kg standing at rest with its breaks realized, If the wagons join together find.

a. their joint speed after the collision.

b. if the collision takes place in 0.1 seconds, what was the acceleration of the moving wagon during the collision

c. what was unbalanced force on the moving wagon during the collision?

d. What was the force on the moving wagon on the stationary wagon?

The Attempt at a Solution



I'm pretty sure the first question uses the law of conservation of momentum

m1u1 + m2u2 = m1v1 + m2v2

But i am just lost with what i need to substitute into this equation :(
 
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ollieman said:

Homework Statement



An empty freight wagon of mass 10000kg rolls at 2.0 ms-1 along a level track and collides with a loaded wagon with a mass of 15000kg standing at rest with its breaks realized, If the wagons join together find.

a. their joint speed after the collision.

b. if the collision takes place in 0.1 seconds, what was the acceleration of the moving wagon during the collision

c. what was unbalanced force on the moving wagon during the collision?

d. What was the force on the moving wagon on the stationary wagon?

The Attempt at a Solution



I'm pretty sure the first question uses the law of conservation of momentum

m1u1 + m2u2 = m1v1 + m2v2

But i am just lost with what i need to substitute into this equation :(

Welcome to PF.

So what kid of collision do you think this is?
Elastic?
Or inelastic?
 
LowlyPion said:
Welcome to PF.

So what kid of collision do you think this is?
Elastic?
Or inelastic?
Thanks for replying to my post LowlyPion

i haven't got any idea, it would be the most basic. Since this is my first year studying physics in a physical science course
 
ollieman said:
Thanks for replying to my post LowlyPion

i haven't got any idea, it would be the most basic. Since this is my first year studying physics in a physical science course

In the equation you provided, any idea about what the terms are?
 
\sum Pi = \sum Pf

From Newtons second law
 
I understand what Conservation of momentum is thanks.

I was asking you what the terms were in the equation you wrote? What is m1 and u1 and ... etc.
 
My text just says i can use either

m1u1 + m2u2 = m1v1 + m2v2

or

\sum Pi = \sum Pf
 
ollieman said:
My text just says i can use either

m1u1 + m2u2 = m1v1 + m2v2

or

\sum Pi = \sum Pf

Yes the first is the two body form of the second.

Now what is m1 and m2 ?
What is u1 and u2 and v1 and v2?
 
m1 mass of the first object
m2 mass of the second object
u1 initial velocity of the first object
u2 initial velocity of the second object
v1 final velocity of the first object
v2 final velocity of the first object

Sorry i just thought it was how it worked, but it must be only how I'm taught
 
  • #10
ollieman said:
m1 mass of the first object
m2 mass of the second object
u1 initial velocity of the first object
u2 initial velocity of the second object
v1 final velocity of the first object
v2 final velocity of the first object

Sorry i just thought it was how it worked, but it must be only how I'm taught

There you go. Good.

Now look at your problem and start assigning values. (Remember since it is inelastic you will have both final velocities equal.)
 
  • #11
I couldn't get it out right :s that's why i posted it on here
 
  • #12
ollieman said:
I couldn't get it out right :s that's why i posted it on here

They give you the mass of the 2 wagons. What do you figure those are then in the equation?

Plug them in.

The velocity of one of the wagons is given. Plug that in.

Then solve for the final velocity.
 
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