Frequency and Length: Solving for String Length

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The discussion revolves around calculating the length of a vibrating string based on frequency and wavelength. The first harmonic wavelength is determined to be 0.592m, leading to a wave speed of 260 m/s when using a frequency of 440 Hz. A new frequency of 523 Hz is then used to find the vibrating length of the string, resulting in a calculated length of 24.9 cm. Participants clarify that this length refers to the portion of the string between the finger and the nut, which vibrates when plucked. The conversation emphasizes the importance of understanding which parts of the string are involved in producing sound.
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Homework Statement


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Homework Equations

The Attempt at a Solution


for the first harmonic, the wavelength is twice the length of string.
so 0.296m x 2 = 0.592m is the wavelength

with the wavelength and frequency known, we solve for v in v = ƒλ

v = 0.592m x 440 Hz = 260 m/s

then to solve for the length of new string , we just use the same v (260 m/s) and use the new frequency (523 Hz) and solve for the L?

if so , I got 24.9 cm
 
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goonking said:

Homework Statement


View attachment 89239

Homework Equations

The Attempt at a Solution


for the first harmonic, the wavelength is twice the length of string.
so 0.296m x 2 = 0.592m is the wavelength

with the wavelength and frequency known, we solve for v in v = ƒλ

v = 0.592m x 440 Hz = 260 m/s

then to solve for the length of new string , we just use the same v (260 m/s) and use the new frequency (523 Hz) and solve for the L?

if so , I got 24.9 cm
With regard to the parts of the string, what length have you calculated as 24.9cm? What length does it ask for?
 
haruspex said:
With regard to the parts of the string, what length have you calculated as 24.9cm? What length does it ask for?
i calculated the length starting from beneath the finger to the nut to be 24.9 cm
 
goonking said:
i calculated the length starting from beneath the finger to the nut to be 24.9 cm
What part of the string is vibrating at 523Hz?
 
haruspex said:
What part of the string is vibrating at 523Hz?
just the 24.9 cm of string between the finger and nut I suppose since the rest isn't vibrating
 
goonking said:
just the 24.9 cm of string between the finger and nut I suppose since the rest isn't vibrating
What is being used to make the string vibrate? What part of the string is it acting on?
 
haruspex said:
What is being used to make the string vibrate? What part of the string is it acting on?
to make the string vibrate, you would have to pluck it, and if you held the string down with your thumb, only the part of the string between your thumb and the nut, will vibrate.
 
goonking said:
to make the string vibrate, you would have to pluck it, and if you held the string down with your thumb, only the part of the string between your thumb and the nut, will vibrate.
You could do that, but you would get hardly any sound out of the violin. Whether played with a bow (as in the diagram) or plucked, it is the part between the bridge and the finger that is plucked or bowed. (The vibration is transferred through the bridge to the broad wooden lamina, and thence to the air inside.)
 
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haruspex said:
You could do that, but you would get hardly any sound out of the violin. Whether played with a bow (as in the diagram) or plucked, it is the part between the bridge and the finger that is plucked or bowed. (The vibration is transferred through the bridge to the broad wooden lamina, and thence to the air inside.)
ah, I had to subtract the two, 29.6 cm - 24.9 cm = 4.7 cm.
 
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goonking said:
ah, I had to subtract the two, 29.6 cm - 24.9 cm = 4.7 cm.
Yes.
 
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