Frequency of oscillation for a hanging mass on a spring?

AI Thread Summary
The frequency of oscillation for a hanging mass on a spring can be calculated using the formula T = 2π√(m/k), resulting in a frequency of approximately 1.9 Hz for a 0.54 kg mass and a spring constant of 75 N/m. The initial displacement does not affect the frequency of oscillation as long as the system remains within the limits of Hooke's law. Larger or smaller displacements will not change the frequency unless the spring behaves nonlinearly, which complicates the analysis. The discussion emphasizes that the oscillation remains harmonic under normal conditions. Thus, the frequency remains constant regardless of the displacement within the elastic limit.
subopolois
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Homework Statement


0.54 kg mass hang vertically from a spring with k= 75 Nm. If the mass is displaced 3 cm vertically and allowed to oscillate, what is the frequency of oscillation?

Homework Equations


T= 2(pi) ((sqrt)(m/K))
F= 1/T

The Attempt at a Solution


T= 2(pi) ((sqrt)(0.54/75))
= 0.5331
F= 1/0.5331
= 1.9 Hz
Now I know I didnt use the displacement, but where would I use it? This was a multiple choice question, and 1.9 Hz is an option... I just don't know if its right
 
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I don't see any reason the initial displacement would affect the frequency of oscillation. Do you?
 
Thats kinda what I am asking...
if the displacement were greater or smaller of the mass, would it change the frequency of oscillation? And if it does, how?
 
Larger displacement mean larger force, larger acceleration and, finally, the same time. For this reason called 'harmonic'.
 
subopolois said:
Thats kinda what I am asking...
if the displacement were greater or smaller of the mass, would it change the frequency of oscillation? And if it does, how?
No, unless Hooke's law were to no longer apply at large displacements, in which case you'd have a nonlinear problem on your hands and believe me you want nothing to do with that.
 
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