Frequency of Siren Perceived at 50m After Fire Engine Passes

AI Thread Summary
The discussion focuses on calculating the perceived frequency of a fire engine's siren as it passes by an observer using the Doppler effect. The speed of sound is given as 343 m/s, and the fire engine travels at 80 km/h while emitting a steady frequency of 440 Hz. For the scenario 100m before the fire engine passes, the Doppler equation is applied correctly. After the fire engine passes, at 50m away, the formula adjusts for the source and observer moving apart, confirming the use of negative values for their velocities. The calculations illustrate how the perceived frequency changes based on the relative motion of the source and observer.
olyviab
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Homework Statement


Assume that the speed of sound in the air is V=343m/s. Use the generalized form of the Doppler equation to solve the following problem.
You are standing 100m away from a long straight road while a fire engine passes by along the road. The fire engine is equipped with a siren which emits a steady frequency of 440Hz. If the fire engine is traveling at 80km/h along the road, what frequency do you preceive for the siren
(a) 100m (measured along the road) before the fire engine passes
(b) 50m (measured along the road) after the fire engine passes


Homework Equations



generalized form of the doppler equation: f ' = [(V + Vocos(θo))/(V-Vscos(θs))]f

The Attempt at a Solution



(b) if the source and the observer are moving away from each other, we have: θs - θo = 180 and since cos180 = -1, we get the equation f ' = [ V/(V+Vs)]f with negative values for both Vo and Vs.
 
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I think that in your question the observer is not moving .. your equation is correct f` = (v/(v+vs))f , was that your question or you have other questions?
 
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