Frequency & Period: Is 1/29000 Correct?

  • Thread starter Thread starter -EquinoX-
  • Start date Start date
  • Tags Tags
    Frequency Period
AI Thread Summary
A frequency of 29 kHz corresponds to a period of 1/29000 seconds, which equals approximately 3.44 x 10^-5 seconds. However, there is confusion regarding the measurement, as one participant mentions reading 0.33 ms from the scope, suggesting a possible misreading. This discrepancy raises questions about whether the correct period should be 0.034 ms instead. Clarification on the correct unit of measurement is necessary for accurate calculations. Accurate interpretation of frequency and period is crucial in understanding wave properties.
-EquinoX-
Messages
561
Reaction score
1

Homework Statement



If I have a frequency of 29k Hz, then the period is 1/29000, which is 3.44 * 10^-5 second
Is this correct?

Homework Equations


The Attempt at a Solution

 
Physics news on Phys.org
Are you not sure about your calculator?
 
I am not sure about whether it is ms or second as when I try to read it from the scope I got .33 ms
 
In that case it should be 0.034 ms.
 
you mean I might have misread the scope?
 
Yes.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top