Friction and cart of mass Question

AI Thread Summary
A 2kg cart is pulled with a horizontal force of 4N across a level surface, facing a coefficient of kinetic friction of 0.12. To find the acceleration, the net force is calculated by subtracting the frictional force from the applied force. The frictional force is determined using the formula coefficient multiplied by mass and gravitational acceleration. After reevaluating the problem, the correct approach led to a successful calculation of the cart's acceleration. The final solution confirms the importance of understanding free body diagrams in solving physics problems.
thomasrules
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I'm having trouble with this if anyone can help thanks.

A cart with a mass of 2kg is pulled across a level desk by a horizontal force of 4N. If the coefficient of kinetic friction is 0.12, what is the acceleration of the cart?
 
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What have you done to try and solve the problem? Start off by drawing a free body diagram.
 
ACTUALY i relooked it...

AND FINALY! I GOT IT!
 
net force = applied force - coeff*m*g
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
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