Friction needed so car does not spin out? how do you do this?

Thread starter nfg5
Start date Sep 30, 2008
Tags

Car Friction Spin

AI Thread Summary

To ensure a car does not skid while rounding a banked curve at a speed of 13.41 m/s, the curve must be designed with a specific banking angle. Given a radius of 213.0 m, the banking angle can be calculated using the formula that relates speed, radius, and gravitational force. The discussion emphasizes the importance of engineering design to create a safe exit ramp that relies solely on the banking angle rather than friction. Participants are encouraged to share their calculations or methods attempted to determine the appropriate angle. Proper design will enhance safety and performance on highway curves.

Sep 30, 2008

nfg5

An engineer must design a curved exit ramp for a highway in such a way that a car, exiting at the posted speed limit of 13.41 m/s (30 mi/hr), does not depend on friction to round the curve without skidding. The radius of the curve is 213.0 m. At what angle with respect to the horizontal must the curve be banked (in degrees)?

Physics news on Phys.org

Oct 1, 2008

Kurdt

Staff Emeritus

Science Advisor

Gold Member

What have you tried?

Thread 'I've come across another fluid pressure problem I don't understand'

Neglect gravity other than that of water; neglect friction. F1=ρgsh=1000*10*1*(1+4)=50000 N; F1=ρgsh=1000*10*0.1*4=4000 N; F3=50000-4000=46000 N?

View full post »

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...

View full post »

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

View full post »