Friction Problem: Find Time to Rest w/ Force of 5.0 N

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The discussion revolves around a friction problem involving two bricks with weights of 24.5 N and 36.8 N, moving at a speed of 1.77 m/sec under a force of 5.0 N. Participants clarify whether the 5.0 N represents the friction force acting on the bricks. Using Newton's 2nd law, the acceleration can be calculated by dividing the net force by the total mass of the bricks. The time it takes for the bricks to come to rest can then be determined using the calculated acceleration. Understanding these concepts is crucial for solving the problem effectively.
Lobos Wolfen
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I have a question on a Friction problem I have received. The question is, If the force acting on the two bricks is 5.0 N, how much time will elapse before the bricks come to rest.

Infomation given- The two bricks are sliding together, the wieghts are 24.5 N and 36.8 N, they are moving at a speed of 1.77 m/sec.
 
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Is 5.0 N the friction force? If so, figure out the acceleration of the bricks using Newton's 2nd law.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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