Frictional Force of a Crate of Potatoes: 13 kg, 40° incline

AI Thread Summary
To find the frictional force on a 13 kg crate of potatoes on a 40° incline, the static friction must be calculated while considering the crate is at rest. The maximum static friction is not necessarily the actual frictional force; instead, it should be determined by analyzing the forces in equilibrium. The relevant forces include weight, friction, and normal force, with weight acting downward, friction opposing motion, and normal force acting perpendicular to the incline. By applying the equation for static friction and ensuring the net force equals zero, the correct frictional force can be derived. Understanding the components of forces along the incline is crucial for solving the problem accurately.
lalahelp
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Homework Statement


A crate of potatoes of mass 13.0 kg is on a ramp with angle of incline 40° to the horizontal. The coefficients of friction are μs = 0.78 and μk = 0.43. Find the frictional force (magnitude) on the crate if the crate is at rest.



Homework Equations


F=ma
Ff=μmgcosα


The Attempt at a Solution



Ff=.78*13*9.81*cos40
=76.2 N


Why is my answer wrong?
 
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You assumed that the static friction would be equal to its maximum possible value (μN). Instead, solve for the value of static friction considering that the crate is in equilibrium.
 
What equation would I use to do that?
 
lalahelp said:
what equation would i use to do that?
The net force is zero.
 
I don't understand it still
 
lalahelp said:
I don't understand it still
What forces act on the crate?
 
the mass and friction
 
lalahelp said:
the mass and friction
The weight, the friction, and the normal force. What direction does each act?
 
the weights acts straight down, friction to the right, and normal force up
 
  • #10
lalahelp said:
the weights acts straight down, friction to the right, and normal force up
Consider force components parallel to the incline and apply ΣF = 0.
 
  • #11
Ok thank you I got it !
 
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