- #1
max1020
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these are technically not homework, i just need more help for my test tomorrow!
I HAVE NO IDEA HOW TO DO THIS! can someone walk me through these and show me the steps! thank you :)
1.A sled is being pulled to the right with a force of 28 N. A frictional force is working opposite the applied force with a magnitude of 17 N. The mass of the sled is 4.5 kg. (a) What is the net force in the x direction? 28 – 17 = 11 N (b) What is the coefficient of friction between the sled’s blades and the surface? m = 0.385
2. A football player with a mass of 86 kg, dives into the end zone and is slowed by the grass after he hits the ground by a force of friction of 580 N. What is µ between the player and the grass? m = 0.69
3. A person pushes horizontally with a force of 350 N on a 68 kg chair to move it across a level floor. The coefficient of friction is 0.37. (a) What is the magnitude of the frictional force? 247 N (b) What is the acceleration of the chair? Fnet = 350 – 247 = 103 N, acceleration = 1.51 m/s2
I HAVE NO IDEA HOW TO DO THIS! can someone walk me through these and show me the steps! thank you :)
1.A sled is being pulled to the right with a force of 28 N. A frictional force is working opposite the applied force with a magnitude of 17 N. The mass of the sled is 4.5 kg. (a) What is the net force in the x direction? 28 – 17 = 11 N (b) What is the coefficient of friction between the sled’s blades and the surface? m = 0.385
2. A football player with a mass of 86 kg, dives into the end zone and is slowed by the grass after he hits the ground by a force of friction of 580 N. What is µ between the player and the grass? m = 0.69
3. A person pushes horizontally with a force of 350 N on a 68 kg chair to move it across a level floor. The coefficient of friction is 0.37. (a) What is the magnitude of the frictional force? 247 N (b) What is the acceleration of the chair? Fnet = 350 – 247 = 103 N, acceleration = 1.51 m/s2