From what height was an object dropped?

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To determine the height from which a ball must be dropped to reach a speed of 5.9 m/s before hitting the ground, kinematic equations can be employed. The initial velocity is zero, and the final velocity is 5.9 m/s. The equation S=(v^2-u^2)/2a can be used to solve for the height, where 'S' represents the distance (height), 'v' is the final velocity, 'u' is the initial velocity, and 'a' is the acceleration due to gravity. Understanding the relevant physics concepts and variables is crucial for solving the problem effectively. The discussion highlights the importance of applying kinematic equations to find the missing variables needed for the solution.
ymehuuh
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Find the height from which you would have to drop a ball so that it would have a speed of 5.9 m/s just before it hits the ground.

vf=5.9
v0=0

Not sure what I can do with only this much information...
 
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Well first of all it would help to know what concepts you're currently covering in your physics class because as far as I can tell, this problem can be solved in a few different ways.

Second of all, what work have you attempted on this problem so far?
 
Use one of the kinematic equations. Think what each equation will do for you. Look at you variables and see what's missing. Then try to find that variable by using the kinematic equations.
 
Figured it out. Used equation S=(v^2-u^2)/2a

THANKS!
 
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