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Having recently completed a session on the simple pendulum in physics, I was curious as to what the solution to θ''+(g/l)sin(θ)=0 for θ(t) was sans the sin(θ)=θ simplification.
sweet springs said:θ''+(g/l)sin(θ)=0
Multiply \theta^. to make {{\theta^.}^2}^., integrate and then take square root to get \frac{dt}{d\theta}