Full solution for the simple pendulum

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The discussion centers on finding a full solution to the simple pendulum equation θ''+(g/l)sin(θ)=0 without simplifying sin(θ) to θ. It highlights that the solution cannot be expressed in elementary functions and points toward elliptic integrals and Jacobi elliptic functions as relevant concepts. Users shared their experiences with various resources, including Wolfram Alpha and Wikipedia, but found it challenging to derive a clear understanding or numerical solution. The conversation suggests using conservation of energy to derive a first-order ordinary differential equation (ODE) as an alternative approach. Overall, the complexity of the pendulum's motion requires advanced mathematical tools for a comprehensive solution.
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Having recently completed a session on the simple pendulum in physics, I was curious as to what the solution to θ''+(g/l)sin(θ)=0 for θ(t) was sans the sin(θ)=θ simplification.
 
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What have you done to satisfy your curiosity?
 
Elliptic integral is the key word.
 
voko, prior to posting I had essentially spent about an hour or so looking through various articles, lecture notes,et c., and hadn't run into anything involving a full solution of that ODE. I did check Wolfram Alpha which pointed me in the direction of the Jacobi elliptic functions, however that did not readily lend itself to understanding the derivation, or finding a numerical solution. I looked under functions.wolfram.com for the Jacobi Amplitude function, and wasn't able to find what I was looking for
 
The full solution of that ODE is not expressible in elementary functions. Have a look here: http://en.wikipedia.org/wiki/Pendulum_(mathematics )
 
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θ''+(g/l)sin(θ)=0
Multiply \theta^. to make {{\theta^.}^2}^., integrate and then take square root to get \frac{dt}{d\theta}
 
sweet springs said:
θ''+(g/l)sin(θ)=0
Multiply \theta^. to make {{\theta^.}^2}^., integrate and then take square root to get \frac{dt}{d\theta}

Or just start with conservation of energy and get the first-order ODE directly.
 

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