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Functions problem

  1. Oct 14, 2008 #1
    1. The problem statement, all variables and given/known data

    part of the question is:

    g:x = b - [tex]\sqrt[3]{x}[/tex]

    x is real

    Solve g(x2) = g(x) - 6

    Show that:

    g(x6) + 4g(x3) [tex]\leq[/tex] 5b + 4 for all real values of x

    3. The attempt at a solution

    If i at least have a hint on how to start the first part i guess i'll be able to do the second one.....

    thank you!!
  2. jcsd
  3. Oct 14, 2008 #2
    Re: OMG FUNCTIONS!!! exams tommoz....

    errmmm it's been solved......

    it was as simple as replacing the x in g(x) by x2

    thanks anyway
  4. Oct 14, 2008 #3


    User Avatar
    Staff Emeritus
    Science Advisor

    Re: OMG FUNCTIONS!!! exams tommoz....

    Do you mean g(x)= b- [tex]\sqrt[3]{x}[/tex]?

    Well, what is g(x2)? You are given the formula for g(x), just put x2 in place of x.

    What are g(x6) and g(x3)? Again, just replace x in the formula for g(x) by the appropriate thing.
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