# Functions problem

1. Oct 14, 2008

### Kushal

1. The problem statement, all variables and given/known data

part of the question is:

g:x = b - $$\sqrt[3]{x}$$

x is real

Solve g(x2) = g(x) - 6

Show that:

g(x6) + 4g(x3) $$\leq$$ 5b + 4 for all real values of x

3. The attempt at a solution

If i at least have a hint on how to start the first part i guess i'll be able to do the second one.....

thank you!!

2. Oct 14, 2008

### Kushal

Re: OMG FUNCTIONS!!! exams tommoz....

errmmm it's been solved......

it was as simple as replacing the x in g(x) by x2

thanks anyway

3. Oct 14, 2008

### HallsofIvy

Staff Emeritus
Re: OMG FUNCTIONS!!! exams tommoz....

Do you mean g(x)= b- $$\sqrt[3]{x}$$?

Well, what is g(x2)? You are given the formula for g(x), just put x2 in place of x.

What are g(x6) and g(x3)? Again, just replace x in the formula for g(x) by the appropriate thing.