Do you mean g(x)= b- [tex]\sqrt[3]{x}[/tex]?Kushal said:Homework Statement
part of the question is:
g:x = b - [tex]\sqrt[3]{x}[/tex]
Well, what is g(x2)? You are given the formula for g(x), just put x2 in place of x.x is real
Solve g(x2) = g(x) - 6
What are g(x6) and g(x3)? Again, just replace x in the formula for g(x) by the appropriate thing.Show that:
g(x6) + 4g(x3) [tex]\leq[/tex] 5b + 4 for all real values of x
The Attempt at a Solution
If i at least have a hint on how to start the first part i guess i'll be able to do the second one...
thank you!
The notation g(x2) means that the function g is being evaluated at the value x2. It is similar to substituting a number in place of x in a function.
To solve this equation, you can first rewrite it as g(x2) - g(x) + 6 = 0. Then, you can use algebraic techniques such as factoring or the quadratic formula to find the values of x that satisfy the equation.
Yes, there can be more than one solution to this equation. It depends on the specific function g and the values of x that make the equation true.
Solving a function problem means finding the values of the independent variable (in this case, x) that make the function equation true. It is a way to find the input values that produce a desired output.
You can check your solution by substituting the value of x into the original equation and seeing if it produces the desired result. You can also use a graphing calculator or software to graph the function and see if the solution aligns with the points on the graph.