Fundamental theorem of calculus

Lee33
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Homework Statement



Let ##[a,b]## and ##[c,d]## be closed intervals in ##\mathbb{R}## and let ##f## be a continuous real valued function on ##\{(x,y)\in E^2 : x\in[a,b], \ y\in[c,d]\}.## We have that ##\int^d_c\left(\int^b_af(x,y)dx\right)dy## and ##\int^b_a\left(\int^d_cf(x,y)dy\right)dx## exist.

Homework Equations



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The Attempt at a Solution



I am wondering how this was solved?

Why is that from the fundamental theorem of calculus we get ##\frac{d}{dt}\int^t_a\left(\int^d_cf(x,y)dy\right)dx## ##=## ##\int^d_cf(t,y)dy## ?
 
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Lee33 said:

Homework Statement



Let ##[a,b]## and ##[c,d]## be closed intervals in ##\mathbb{R}## and let ##f## be a continuous real valued function on ##\{(x,y)\in E^2 : x\in[a,b], \ y\in[c,d]\}.## We have that ##\int^d_c\left(\int^b_af(x,y)dx\right)dy## and ##\int^b_a\left(\int^d_cf(x,y)dy\right)dx## exist.

Homework Equations



None


The Attempt at a Solution



I am wondering how this was solved?

Why is that from the fundamental theorem of calculus we get ##\frac{d}{dt}\int^t_a\left(\int^d_cf(x,y)dy\right)dx## ##=## ##\int^d_cf(t,y)dy## ?

Let F: [a,b] \to \mathbb{R}: x \mapsto \int_c^d f(x,y)\,dy, and apply the fundamental theorem of calculus to \frac{d}{dt}\int_a^t F(x)\,dx.
 
I am not sure what exactly to do. Can you elaborate further please?
 
Lee33 said:
I am not sure what exactly to do. Can you elaborate further please?

Can you please cite what exactly you mean with "the fundamental theorem of calculus"?
 
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Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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