G of f injective, but g not injective

  • Thread starter Thread starter gotmilk04
  • Start date Start date
  • Tags Tags
    Injective
gotmilk04
Messages
44
Reaction score
0

Homework Statement


Give an example of a map f:A\rightarrowB and a map g:B\rightarrowC where g of f is injective but g is not injective.


Homework Equations





The Attempt at a Solution


I'm not really sure what they are asking for.
 
Physics news on Phys.org
In a nutshell, find two functions, f and g, so that g \circ f is one-to-one, but f \circ g is not.
 
So it's basically just guess and check?
 
It doesn't have to be. Think about arranging it so that g is injective on the image of f but not on the entire domain of g.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top