Galilean Transformation Question

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In the discussion, the Galilean transformation equation for the x-coordinate is clarified, emphasizing that x' = x - vt is correct because the origin of frame S' moves towards the object in frame S. At t=0, both frames have the same coordinates, but as time progresses, the x' coordinate decreases since S' is moving towards the object. A visual representation aids in understanding the relationship between the two frames. An example illustrates that if an object moves with S', its coordinates in S are (vt, t), while in S' they are (0, t), confirming the necessity of the correct transformation. Understanding these concepts is crucial for further studies in special relativity.
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What happens if I have 2 frames,S and S', with S as my rest frame and S' moving in the +ve x direction (towards the right). Why is it that the equation for the galilean transformation for the x-coordinate is x'=x-vt instead of x'=x+vt ?
 
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Think of an object lying on the positive x-axis (it therefore also lies on the x'-axis). At t=0 the x and x' coordinate of the object are the same, but since the origin in S' moves towards the object (as seen from S. In S' the object moves towards the origin.) the x' coordinate decreases with time. So x'=x-vt is the right equation.

Drawing a picture also helps.
 
The primed coordinates are the coordinates measured by the "moving" frame. Take a simple case: Imagine an object moving along with the origin of S'. After a time t, the S frame says the object's coordinates are (x,t) = (vt,t). Of course, the S' frame gives the coordinates as (x', t) = (0, t). Using x'=x+vt gives the wrong answer.
 
hey thanks alot, I've gottit, sorry if my questions are a little too simple, I'm mostly self-taught.
 
There's no problem with us:it's essential for you to have these problems clear,especially if you want to go into studying SR,where things are a bit more difficult...

Daniel.
 
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