Galileo's experiment and equivalence principle

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Galileo's experiment at Pisa illustrates the Equivalence Principle by demonstrating that the acceleration of falling objects is constant regardless of their mass. This leads to the conclusion that the ratio of gravitational mass to inertial mass remains a constant value, although it does not have to equal one. The choice of the gravitational constant, G, simplifies calculations by setting this ratio to one, but it could theoretically be adjusted without affecting the fundamental principles. The discussion emphasizes that the experiment supports the idea that all objects experience the same gravitational acceleration. Overall, Galileo's findings laid the groundwork for understanding the relationship between mass and gravity in physics.
AlonsoMcLaren
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Why do we say that Galileo's experiment at Pisa is an illustration of Equivalence Principle?

All we know is that

G* (mass of earth)*(gravitational mass of object)/(R^2) = (intertial mass of object)*a

Therefore,
a=G* (mass of earth)*(gravitational mass of object)/(R^2 * (inertial mass of object))

The experiment shows that a does not change for different objects.
But this only guarantees that (gravitational mass of object)/(inertial mass of object)= a constant, which is not necessarily 1.
 
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AlonsoMcLaren said:
But this only guarantees that (gravitational mass of object)/(inertial mass of object)= a constant, which is not necessarily 1.

We choose the value of G so that that constant is equal to 1. We don't have to - it just makes the math simpler. We could, if we wanted, say that that constant was equal to 2, and use a value of G which was greater by a factor of four to make the calculation match the force that we measure experimentally ... but why bother?
 
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