Atoms Absorbing Light & Emitting Photons: The Gas Experiment

In summary, the process of gas atoms absorbing light and emitting photons depends on the constituents of the gas and the wavelength of the photon. The absorbed photon can cause the atom to go to a higher energy state and can also lead to the production of multiple photons. The constituency of the gas can be determined by analyzing the spectrum of the emitted radiation, as each atomic species has its own unique spectrum. This is also how we can determine the composition of stars.
  • #1
radaballer
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If a gas is bombarded with light will the atoms absorb the light and emit photons of an equal energy level?
 
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  • #2
radaballer said:
If a gas is bombarded with light will the atoms absorb the light and emit photons of an equal energy level?

It is more complicated and depends on the constituents of the gas. Typically when a photon is absorbed an atom or molecule will go to a higher energy state. What happens next depends on the material and the photon wavelength.
 
  • #3
They don't have to emit photons of an equal energy level... I'm talking about photon absorption...
For a rough example, suppose you have three energy levels... [itex] E_{3} > E_{2} >E_{1}[/itex]... if the absorbed photon has energy [itex]E= |E_{3}- E_{1}|[/itex], then you can have the production of 2 photons of energy [itex]\epsilon_{a}=|E_{3}- E_{2}|[/itex] and [itex]\epsilon_{b}=|E_{2}-E_{1}|[/itex]...
 
  • #4
mathman said:
It is more complicated and depends on the constituents of the gas. Typically when a photon is absorbed an atom or molecule will go to a higher energy state. What happens next depends on the material and the photon wavelength.

Is there any particular way to determine the constituency of gas as it relates to the release of photons
 
  • #5
radaballer said:
Is there any particular way to determine the constituency of gas as it relates to the release of photons

Yes. The spectrum of the emitted radiation. Each atomic species has its own spectrum. This is how we know what stars are made of, among other things.
 

What is the purpose of the "Atoms Absorbing Light & Emitting Photons: The Gas Experiment"?

The purpose of this experiment is to observe and understand the behavior of atoms when they are exposed to light. In particular, we will be studying how atoms absorb and emit photons, which are the fundamental units of light.

How does the gas used in the experiment affect the results?

The gas used in the experiment will determine the specific wavelengths of light that the atoms will absorb and emit. Each type of gas has distinct energy levels that correspond to specific wavelengths of light, so using different gases will produce different results.

What is the process of "absorption" and "emission" in relation to atoms and photons?

Absorption occurs when an atom absorbs a photon of light, causing an electron to jump to a higher energy level. This absorption is specific to the energy level of the photon, and the atom will only absorb photons with matching energy levels. Emission, on the other hand, happens when an electron in an excited state drops down to a lower energy level, releasing a photon of light in the process.

How can we measure the absorption and emission of photons by atoms?

We can measure the absorption and emission of photons by using a spectrometer. This device separates light into its different wavelengths, allowing us to observe which wavelengths are being absorbed and emitted by the atoms. By analyzing the data from the spectrometer, we can determine the energy levels of the atoms and the wavelengths of light they are interacting with.

What are some potential real-world applications of understanding atoms absorbing light and emitting photons?

Understanding this process is crucial in many areas of science and technology. For example, it is essential in the development of new materials, as well as in fields such as astronomy and chemistry. It also has practical applications in areas such as solar energy, lasers, and medical imaging.

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