Gas liquid contact in stripping column

AI Thread Summary
The discussion focuses on the mathematical derivation of a formula related to gas-liquid contact in a stripping column. The initial equation (1) is presented, and the user seeks clarification on how to transition to the final result (2). Another participant suggests a correction to the formula, indicating that the denominator should be adjusted to reflect the correct summation. The conversation emphasizes the importance of proper notation in LaTeX for clarity. The thread highlights the collaborative effort to solve a technical problem in chemical engineering.
RAfAEL_SP
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\frac{x[Ain]-x[Aout][/SUB][/SUB]}{x[Ain]-x[out][/SUB][/SUB]}=\frac{\sum s^{K}-1}{\sum s^K} (1)

for k = 0 to n

Final result:

\frac{x[Ain]-x[Aout][/SUB][/SUB]}{x[Ain]-x[/SUB][/SUB]} = \frac{{S-S^{n+1}}}{1-S^{n+1}}

(2)

Does anyone know how to get from (1) to (2).
 
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Welcome to PF!

Hi RAfAEL_SP! Welcome to PF! :smile:

(use _ not SUB in latex, and use tex rather than itex for fractions that ou don;t want to be too tiny! :wink:)
c said:
\frac{x[Ain]-x[Aout][/SUB][/SUB]}{x[Ain]-x[out][/SUB][/SUB]}=\frac{\sum s^{K}-1}{\sum s^K} (1)

for k = 0 to n

Final result:

\frac{x[Ain]-x[Aout][/SUB][/SUB]}{x[Ain]-x[/SUB][/SUB]} = \frac{{S-S^{n+1}}}{1-S^{n+1}}

(2)

Does anyone know how to get from (1) to (2).

I think you mean \frac{\sum s^{K-1}}{\sum s^K}
Then eg the denominator is (∑sK)/(1 - S) :wink:
 
The exponent is just k
 
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