Gas Tank Leak Rate Problem: Modeling and Calculating with V(t)=90(1-t/18)^2

xdeanna
Messages
24
Reaction score
0
The gas tank of a parked pickup truck develops a leak. The amount, V, in liters, of gas remaining in the tank after t hours can be modeled by the function
V(t)= 90(1-t/18)^2 , t is between 0 and 18.

b) how fast is the gas leaking from the tank at t=12h

I tried V(12) and V'(12) but still didn't get the answer at the back of the book. Shouldn't it be the first derivative at t=12?
 
Physics news on Phys.org
xdeanna said:
The gas tank of a parked pickup truck develops a leak. The amount, V, in liters, of gas remaining in the tank after t hours can be modeled by the function
V(t)= 90(1-t/18)^2 , t is between 0 and 18.

b) how fast is the gas leaking from the tank at t=12h

I tried V(12) and V'(12) but still didn't get the answer at the back of the book. Shouldn't it be the first derivative at t=12?

Yes, you should compute
\frac{dV}{dt}
and evaluating for t =12

You should get 3.33 l/h
 
Thanks :) I got that too.. the book is wrong
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top