Gauss' Law: Electric Field of Spherical Shell Insulator

AI Thread Summary
To find the y-component of the electric field at point P located at (0, -5 cm) due to a spherical shell insulator with inner radius 4 cm and outer radius 6 cm carrying a total charge of +9 C, Gauss's Law is applicable. The problem involves recognizing the spherical symmetry, which indicates that the electric field will be radial and uniform in magnitude. By applying Gauss's theorem, one can draw an imaginary sphere centered on the shell's center that passes through point P. The integral can then be simplified by taking the electric field E outside the integral, allowing for the evaluation of the total charge enclosed within the surface. This approach leads to the determination of the electric field at the specified point.
miniMitts27
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Given a spherical shell insulator as defined by an inner radius a = 4 cm and an outer radius b = 6 cm and carries a total charge of Q = + 9 C (1 C = 10-6 C). (You may assume that the charge is distributed uniformly throughout the volume of the insulator).
What is Ey, the y-component of the electric field at point P which is located at (x,y) = (0, -5 cm)? (picture of situation is attached)

Basically I just don't even know where to start. I realize that it's a Gauss' Law problem... I just don't know where to go from here. Any help would be greatly appreciated!
 

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Hi miniMitts27
You are correct, whenever you see a problem like this with spherical symmetry, Gauss's theorem sounds like the weapon of choice.
So what does the theorem say (in your case) ?
You can draw a sphere centred on your shell's centre and passing through your point P
You know by symmetry that the field E will be radial and have everywhere the same magnitude
So just write Gauss's theorem with this particular surface and evaluate the integral which, thanks to this symmetry will allow you to take E outside and just evaluate the total charge inside the imaginary surface
Cheers...
 
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