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"In an argon ion laser ( λ = 514nm) the minimum beam waist is 1.0mm and is close to the plane mirror. Calculate the radius of curvature of the beam at the output mirror. 1.15m away"

Attempt at a solution:

θ = 2λ/pi W0

^{2}

R = Z + Z

_{R}

^{2}/Z

Z

_{R}= piW

_{0}

^{2}/ λ

I used

W0 = min beam waist = 1.00 mm

Z= distance from beam waist to mirror = 1.15m

And found Z

_{r}with the formula and used it in the Radius of curvature, R formula but got the worng answer. I got R = 33.5m

The answer given is R = 3.08m