soupdejour
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I am stuck with Gaussian units. If the field in vacuum is
E = \frac{Q}{r^2}
Is the field in a dielectric
E = \frac{Q}{\epsilon_r r^2}
, or is it unchanged?
E = \frac{Q}{r^2}
Is the field in a dielectric
E = \frac{Q}{\epsilon_r r^2}
, or is it unchanged?