General question about circuits

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When two batteries are connected in parallel without resistors or capacitors, the total current can be found by adding the individual currents from each battery. The overall voltage remains the same as that of a single battery, assuming all batteries have equal voltage ratings. This configuration increases the total ampere-hour rating, allowing for a higher capacity. It is important to ensure that all batteries are of the same voltage to avoid complications. Properly connecting batteries in parallel can enhance the performance of a circuit.
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I have a somewhat general question...If two batteries in a circuit are connected in parallel with no resistors or capacitors in between, would you find the total current by just adding them together, or would you have to add 1/V ?
 
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The overall voltage is the same as the rating for any single cell. That is assuming that all cells have equal voltage rating! Yes, the max total current is the same as the sum of current provided by individual batteries. Therefore you get a higher ampere-hour rating.
 
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Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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