General Relativity-surface gravity in killing horizon

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SUMMARY

The discussion focuses on proving the equation \(\kappa^2=-\frac{1}{2}(\bigtriangledown_{\mu}V_{\nu})(\bigtriangledown^{\mu}V^{\nu})\) in the context of General Relativity, specifically related to surface gravity in a Killing horizon. Participants emphasize the importance of using the properties of covariant derivatives, particularly \(\chi^{\lambda}\bigtriangledown_{\lambda}\chi^{\nu}=-\kappa\chi^{\nu}\) and \(\bigtriangledown_{(\mu}\chi_{\nu)}=0\), to simplify the proof. The solution involves contracting terms after applying these properties, ultimately leading to the desired result.

PREREQUISITES
  • Understanding of General Relativity concepts, particularly Killing vectors.
  • Familiarity with covariant derivatives and their properties.
  • Knowledge of tensor calculus, specifically contraction of tensors.
  • Experience with the metric tensor and its role in lowering and raising indices.
NEXT STEPS
  • Study the properties of Killing vectors in General Relativity.
  • Learn about covariant derivatives and their applications in tensor calculus.
  • Explore the concept of surface gravity in the context of black holes.
  • Investigate the implications of the equation \(\kappa^2=-\frac{1}{2}(\bigtriangledown_{\mu}V_{\nu})(\bigtriangledown^{\mu}V^{\nu})\) in various spacetime geometries.
USEFUL FOR

This discussion is beneficial for physicists, mathematicians, and students specializing in General Relativity, particularly those interested in the mathematical foundations of black hole physics and surface gravity concepts.

nikhilb1997
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1. Homework Statement
Prove the following-

\kappa^2=-1/2(\bigtriangledown_{\mu}V_{\nu})(\bigtriangledown^{\mu}V^{\nu})
Given, the following,
\chi^{\lambda}\bigtriangledown_{\lambda}\chi^{\nu}=-\kappa\chi^{\nu}
\bigtriangledown_{(\mu}\chi_{\nu)}=0
\chi_{[\mu}\bigtriangledown_{\nu}\chi_{\theta]}=0

Homework Equations



\kappa^2=-1/2(\bigtriangledown_{\mu}V_{\nu})(\bigtriangledown^{\mu}V^{\nu})
\chi^{\lambda}\bigtriangledown_{\lambda}\chi^{\nu}=-\kappa\chi^{\nu}
\bigtriangledown_{(\mu}\chi_{\nu)}=0
\chi_{[\mu}\bigtriangledown_{\nu}\chi_{\theta]}=03. The Attempt at a Solution
I do not know how to start as the equation to prove has a raised covariant derivative. I tried to use the metric to lower it but I got stuck at how the metric would affect the equation. So please help.
 
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nikhilb1997 said:
1. Homework Statement
Prove the following-

\kappa^2=-1/2(\bigtriangledown_{\mu}V_{\nu})(\bigtriangledown^{\mu}V^{\nu})
Given, the following,
\chi^{\lambda}\bigtriangledown_{\lambda}\chi^{\nu}=-\kappa\chi^{\nu}
\bigtriangledown_{(\mu}\chi_{\nu)}=0
\chi_{[\mu}\bigtriangledown_{\nu}\chi_{\theta]}=0



Homework Equations



\kappa^2=-1/2(\bigtriangledown_{\mu}V_{\nu})(\bigtriangledown^{\mu}V^{\nu})
\chi^{\lambda}\bigtriangledown_{\lambda}\chi^{\nu}=-\kappa\chi^{\nu}
\bigtriangledown_{(\mu}\chi_{\nu)}=0
\chi_{[\mu}\bigtriangledown_{\nu}\chi_{\theta]}=0


3. The Attempt at a Solution
I do not know how to start as the equation to prove has a raised covariant derivative. I tried to use the metric to lower it but I got stuck at how the metric would affect the equation. So please help.

Take \chi_{[\mu}\bigtriangledown_{\nu}\chi_{\theta]}=0, use \bigtriangledown_{(\mu}\chi_{\nu)}=0 to get rid of half of the terms, then contract with \nabla^{\mu} \chi^{\nu}
 
clamtrox said:
Take \chi_{[\mu}\bigtriangledown_{\nu}\chi_{\theta]}=0, use \bigtriangledown_{(\mu}\chi_{\nu)}=0 to get rid of half of the terms, then contract with \nabla^{\mu} \chi^{\nu}
Thanks a lot. I did the first two steps but I didn't know what to do next. Contracting gave the required result.
 

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