Hello, 1. The problem statement, all variables and given/known data find the general solution to cos3θ = sin2θ 2. Relevant equations 3. The attempt at a solution I know that sinθ = cos(π/2 - θ) but I am unsure of how to apply this when I have sin2θ. Do I say that sin2θ = cos2(π/2 - θ)? I think not because when I do this my answer does not agree with what my book says. Thanks!