- #1
BOAS
- 553
- 19
Hello,
find the general solution to cos3θ = sin2θ
I know that sinθ = cos(π/2 - θ) but I am unsure of how to apply this when I have sin2θ.
Do I say that sin2θ = cos2(π/2 - θ)?
I think not because when I do this my answer does not agree with what my book says.
Thanks!
Homework Statement
find the general solution to cos3θ = sin2θ
Homework Equations
The Attempt at a Solution
I know that sinθ = cos(π/2 - θ) but I am unsure of how to apply this when I have sin2θ.
Do I say that sin2θ = cos2(π/2 - θ)?
I think not because when I do this my answer does not agree with what my book says.
Thanks!