jeff1evesque
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Statement:
Consider two dipole antennas, oriented 90degrees apart [imagine the x-y plane, let "a" be the dipole oriented along the x-axis, and the "b" be the dipole oriented along the y-axis]. If "a" dipole radiates cos(\omega t) and "b" dipole radiates sin(\omega t), the field radiated by the two antennas will be circularly polarized:
\vec{E}(z, t) = E_{0}[cos(\omega t - \beta z)\hat{x} + sin(\omega t - \beta z)\hat{y}] (#1)
Relevant Question:
Ok I almost get it now. Now in terms of a specific distance, say in the \hat{x} direction, the cosine function has traveled a distance \omega t (as did the sine function in it's respective axis). But I don't understand why To find electric field at a given location in the \hat{z} direction, we subtract the distance traveled \omega t by the wave number times distance in z, or \beta z - for each component \hat{x}, \hat{y}. The wave number is the wavelength of the sinusoid per unit distance. What happens when we take this wave number \beta and multiply it by z? What does that represent, I cannot see the relation between the two (\omega t and \beta z)?
Does one unit length of z = 1 for \beta z \hat{x} and \beta z \hat{y} correspond to a length of \frac{2\pi}{\lambda} in the \hat{z} direction?
Consider two dipole antennas, oriented 90degrees apart [imagine the x-y plane, let "a" be the dipole oriented along the x-axis, and the "b" be the dipole oriented along the y-axis]. If "a" dipole radiates cos(\omega t) and "b" dipole radiates sin(\omega t), the field radiated by the two antennas will be circularly polarized:
\vec{E}(z, t) = E_{0}[cos(\omega t - \beta z)\hat{x} + sin(\omega t - \beta z)\hat{y}] (#1)
Relevant Question:
Ok I almost get it now. Now in terms of a specific distance, say in the \hat{x} direction, the cosine function has traveled a distance \omega t (as did the sine function in it's respective axis). But I don't understand why To find electric field at a given location in the \hat{z} direction, we subtract the distance traveled \omega t by the wave number times distance in z, or \beta z - for each component \hat{x}, \hat{y}. The wave number is the wavelength of the sinusoid per unit distance. What happens when we take this wave number \beta and multiply it by z? What does that represent, I cannot see the relation between the two (\omega t and \beta z)?
Does one unit length of z = 1 for \beta z \hat{x} and \beta z \hat{y} correspond to a length of \frac{2\pi}{\lambda} in the \hat{z} direction?
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