- #1
needhelp83
- 199
- 0
Using the formula for the sum of geometric series, show that the values of p(n) sum to 1
p(n)=[tex](1 - \alpha)^n \alpha[/tex]
My attempt:
[tex]
\alpha
\sum^\infty_{{\bf n=0}}
(1- \alpha)^n
[/tex]
I am not sure where to go from here. Any help to show this is true!
p(n)=[tex](1 - \alpha)^n \alpha[/tex]
My attempt:
[tex]
\alpha
\sum^\infty_{{\bf n=0}}
(1- \alpha)^n
[/tex]
I am not sure where to go from here. Any help to show this is true!