Geometrical problem related to thin film interference

AI Thread Summary
The discussion focuses on proving the optical path length difference in thin film interference, specifically the equation Δ=n(BC+CD)-BE=2nd cos(r). The poster is struggling to derive the term 2nd cos(r) and has attempted trigonometric methods without success. They clarify that this inquiry is independent of their coursework and is aimed at understanding the concept of thin film interference under non-perpendicular incidence. Visual aids are provided to assist in the explanation. The thread highlights the challenges of applying trigonometry to this optical problem.
khaos89
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Look at the picture below, I have to prove that the optical path length difference is

\Delta=n(BC+CD)-BE=2nd\cos(r)

[PLAIN]http://img200.imageshack.us/img200/2271/schermata082455775alle1.th.png

The problem is just how to get 2nd\cos(r)

I actually don't have any idea :\

I have tried to work with trigonometry but no luck yet...

(I am posting it here because it's not related to course work, i am just trying to understand how it works when we don't have perpendicular incidence)
 
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Sorry, here we go with the pic:

[PLAIN]http://img193.imageshack.us/img193/2271/schermata082455775alle1.png
 
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Thanks a lot :)
 
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