Geometry: Find Min Length & Perimeter of Hexagon ABCDEF

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Hexagon ABCDEF features equal diagonals AC, CE, and EA, with angles ABC and CDE at 90 degrees and all sides as different integers. The minimum perimeter for AC equal to the square root of 85 requires applying Pythagoras' Theorem and the triangle inequality to determine side lengths. To find the smallest length of AC while maintaining the hexagon's properties, the same mathematical principles must be utilized. The discussion emphasizes the importance of listing possible integer values for the sides and ensuring they meet the triangle inequality conditions. Overall, the problem involves a systematic approach to geometry and integer constraints.
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Hexagon ABCDEF has the following properties:
-diagonals AC, CE and EA are all the same length
-angles ABC and CDE are both 90 degrees
-all the sides of the hexagon have lengths which are different integers

1) what is the minimum perimeter of ABCDEF if AC = squareroot of 85?

2) what is the smallest length of AC for which ABCDEF has all these properties?

3) what is the minimum perimeter in this case (case 2) ?
 
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Looks like homework. Show your thoughts/work first.
 
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OK, here's a hint to start you out. Apply constraints on the sides to meet the conditions. You'll need Pythagoras' Theorem and the triangle inequality for starters.
 
hi, what do you mean by triangle inequality? could you please enlighten me? thanks.
 
therisingpower said:
hi, what do you mean by triangle inequality? could you please enlighten me? thanks.

Triangle inequality : The sum of the lengths of any two sides of a triangle is always greater than the third.

Here's an outline of how to approach the problem, you must flesh out the details yourself :

For part 1)

1) You're given that all the diagonals are the same length. The 3 diagonals divide the figure into three peripheral triangles and one central triangle. You only need to concern yourself with the three peripheral triangles.

2) You know that two of the angles (at least) opposite the diagonals are right angles. From Pythagoras' Theorem, come up with two equations relating the squares of the lengths of four of the sides.

3) Since you know that all the lengths are different integers, list out the possible values that the four sides can take.

4) That leaves one more peripheral triangle, and you're not restricted to a right triangle here. You do however, know the length of one side (the diagonal). Use the triangle inequality to come up with the minimum sum of lengths of the other two sides. Deduce possible values of the other two sides that sum up to this length, and see if they're admissible. If not, add one to that minimum sum and try again.

For part 2)

Use Pythagoras theorem and listing of squares of integers to see if you can come up with two distinct sets of squares that add up to the same integer. This will be either less than or equal to 85, naturally, given the previous info.

For part 3)

Work thru' the same logic as before and find possible minimal lengths for the last two sides given this new diagonal length.
 
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thanks! =) i finally understand..
 
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