Gibbs and Helmholtz equations for thermodynamic processes

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The discussion focuses on determining the change in Gibbs and Helmholtz free energy for various thermodynamic processes: adiabatic, isothermic, constant volume, and constant pressure. Key equations include ΔG = ΔH - TΔS and ΔA = ΔU - TΔS, with specific conditions applied for each process, such as setting dT, dP, or dV to zero. The importance of considering whether chemical reactions are involved is highlighted, as the equations primarily pertain to reactions at constant temperature and pressure. Derivations for calculating ΔS using both heat transfer and Maxwell's relations are discussed, emphasizing the need for careful mathematical verification. Overall, the applicability of these equations depends on the specific conditions of the thermodynamic processes being analyzed.
tag16
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For a thermodynamic process, what equations would be used to find the change in Gibbs and Helmholtz free energy when:
a.)The process is adiabatic
b.)The process is isothermic
c.)The process is at constant volume
d.)The process is at constant pressure

I know ΔG=ΔH-TΔS and ΔA=ΔU-TΔS but do these equations apply to all four processes?
 
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I think you need to get into the thermodynamic partial derivative definition of these processes, i.e.

Gibbs Energy:
dG = -SdT + VdP
Helmholtz Energy:
dA = - SdT - PdV

Now you set the appropriate terms to zero.

i.e.
adiabatic: is it a reversible process?
isothermic: dT=0
isobaric (const pressure): dP=0
const vol: dV=0
 
Does the process include chemical reactions?
 
Basically, I'm asking if you were given a PV graph similar to this:

http://www.websters-online-dictionary.org/images/wiki/wikipedia/commons/thumb/d/dc/Stirling_Cycle.png/200px-Stirling_Cycle.png


How would you find ΔG and ΔA for the processes 1 to 2, 2 to 3, 3 to 4 and 4 to 1?
 
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For 1 to 2:
ΔG = ΔH - TΔS
ΔA = ΔU - TΔS

ΔU=NCvΔT=0
ΔH=NCpΔT=0

so ΔA = ΔG=-TΔS; you know T but need to find ΔS. There are two derivations; either will work for you. I'm going fast so may have mixed up negative signs & numerators/denominators, you need to double check the math when you do it yourself to make sure nothing is wrong.

Derivation 1
ΔU = Q + W = 0 b/c ΔU = 0.
Q = -W
dW = -PdV
dW= -(NRT/V)dV (plugged in ideal gas law)
W = -NRTln(V2/V1)
so Q = NRTln(V2/V1)
ΔS = Q/T = -NRln(V2/V1)Derivation 2 (my preference)
Use Maxwell's relations.
(dS/dV) at const T = (dP/dT) at const V. Plug in ideal gas law.
So dS/dV = NR/V; integrate to get ΔS = NR ln (V2/V1).
 
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For 2 to 3:
Isochoric Cooling - Const Volume.

ΔU = NCvΔT = Q + W.
W = PΔV so W = 0.

ΔU = Q = NCvΔT.
ΔH=ΔU+Δ(PV)=ΔU+VΔP
 
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tag16 said:
I know ΔG=ΔH-TΔS and ΔA=ΔU-TΔS but do these equations apply to all four processes?

I was asking whether chemical reactions are taking place (which, as I learned from your answer, is not the case) because the formulas above refer to the change of G or A due to a chemical reaction taking place at constant T and p. The "Delta" is not simply an abbreviation for a difference here but
\Delta X=\sum_i \nu_i \partial X/\partial n_i |_{T, P} which the nu_i being the stochiometric coefficients of the reaction taking place. So this formula is little helpful when you consider a process which does not involve chemical reactions.
 
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