Given the Volume, Find the Number of Atoms

  • Thread starter Thread starter asifion
  • Start date Start date
  • Tags Tags
    Atoms Volume
AI Thread Summary
The discussion focuses on calculating the average distance between atoms or rubber balls within a given volume using the formula D = (2.5)^3 / N. The participants explore the relationship between the number of balls and their average distance, suggesting that the average distance is measured from center to center. The concept of "mean free path" is introduced, emphasizing its relevance to molecular movement in gases and the density of molecules. There is a consensus that the speed of the balls affects their interaction, with a need for clarification on how speed influences the scenario. The conversation highlights the importance of understanding these physical principles in relation to the problem at hand.
asifion
Messages
18
Reaction score
0
Homework Statement
A mad engineer builds a cube, 2.5 m on a side, in which 6.2-cm-diameter rubber balls are constantly sent flying in random directions by vibrating walls. He will award a prize to anyone who can figure out how many balls are in the cube without entering it or taking out any of the balls. You decide to shoot 6.2-cm-diameter plastic balls into the cube, through a small hole, to see how far they get before colliding with a rubber ball. After many shots, you find they travel an average distance of 2.8 m. How many rubber balls do you think are in the cube?
Relevant Equations
not sure but: N/V=p/(k_B*T)
pV=nRT
V/N = distance between atoms?
So, I was thinking that the total volume of the cube divided by the number of atoms (or rubber balls) should intuitively give the average distance between each ball.

What I did was:
N = number of balls
D = avg distance between balls

(2.5)^3 / N = D
(2.5)^3 / D = N
D = 2.8 - 2 * radius (I'm assuming the given average distance is from center to center of each sphere)

2.5^3/(2.8-.062) = 5.7 balls
 
Last edited:
Physics news on Phys.org
Have you covered the topic of "mean free path" of molecules in a gas?

I think the problem should have stated that the speed at which you shoot the plastic balls is similar to the average speed of the rubber balls. (For example, if the plastic balls were fired at an extremely slow speed, they would hardly go any distance inside the box before being hit by a rubber ball.)
 
  • Like
Likes asifion
TSny said:
Have you covered the topic of "mean free path" of molecules in a gas?

I think the problem should have stated that the speed at which you shoot the plastic balls is similar to the average speed of the rubber balls. (For example, if the plastic balls were fired at an extremely slow speed, they would hardly go any distance inside the box before being hit by a rubber ball.)

Yes we have, but I don't think the professor went into detail. But when using the equation, I get the correct answer. Thanks.
 
Mean free path in a gas is related to the number of molecules per unit volume.
 
  • Like
Likes asifion
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top