1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Golfing on North Pole (equation of motion)

  1. May 2, 2016 #1
    1. The problem statement, all variables and given/known data

    Hi everybody! I'm stuck at a problem I was given in my special relativity theory class, can anybody help?

    A golfer is on the North Pole, on a flat surface perpendicular to the earth axis and without friction. He places himself at distance L from the pole and hits the ball exactly to the North Pole with an initial velocity v. Calculate at which distance from the hole the ball rolls, in which you must solve the Newton's equation of motion in the coordinate system rotating with the earth.
    Tip: use Cartesian coordinates (x1,x2,x3) with x3 along the earth axis and write the equation of motion for the complex combination z = x1 + ix2.

    2. Relevant equations

    Coriolis acceleration, coriolis force

    3. The attempt at a solution

    So with a few students we managed to get an equation of motion, but then we're stuck because of the complex conjugate number:

    [tex]
    \ddot{r} = - \vec{ω} \times (\vec{ω} \times \vec{r}) - 2(\vec{ω} \times \dot{\vec{r}}) \\
    \implies \ddot{r} + 2(\vec{ω} \times \dot{\vec{r}}) + \vec{ω} \times (\vec{ω} \times \vec{r}) = 0 \\
    (\ddot{r_x}, \ddot{r_y}, 0) + 2 (- \dot{r_y} ω_z, \dot{r_x} ω_z, 0) - (r_x ω_z^2, r_y ω_z^2, 0) = 0 \\
    \mbox{we combined the two equations (for x and y) and replaced the } r_x + r_y \mbox{ by } x_1 + ix_2 \\
    \implies \ddot{z} + 2ω_z \dot{\bar{z}} - ω_z^2 z = 0
    [/tex]

    What do you guys think to begin with? The complex conjugate is strange, it's making the differential equation really hard, too hard for our level. We've checked everywhere but couldn't find a mistake. Any suggestions?

    Thanks a lot in advance!

    Julien.
     
  2. jcsd
  3. May 2, 2016 #2

    mfb

    User Avatar
    2016 Award

    Staff: Mentor

    You are probably allowed to neglect higher-order effects, which means you know ##\dot z## (and also its complex conjugate) when calculating ##\ddot z##.

    Mathematically, the complex conjugate is just a minus sign for x2.

    This problem is so much easier in non-rotating coordinates... at least you can use them to check the result.
     
  4. May 2, 2016 #3
    @mfb thanks for your answer, but I am afraid it doesn't help much. I know what the conjugate of a complex number is, but I can't solve the differential equation with it inside. I tried to make it disappear somehow but no luck so far! :)
     
  5. May 2, 2016 #4

    mfb

    User Avatar
    2016 Award

    Staff: Mentor

    I don't think you need a full analytic solution.

    But thinking about it, are you sure it is right with the complex conjugate? There should be a factor of i somewhere.
     
  6. May 2, 2016 #5
    @mfb Well I need to find an equation of motion relative to the earth axis I imagine, right? I forgot to give an indication: we can check the formula we get with L = 200m and v = 30m/s and we should get ca. 10 cms.


    Julien.
     
  7. May 2, 2016 #6
    Also, another student told me we can ignore the centrifugal acceleration (why??). That simplifies the equation a little bit, but still doesn't solve the complex conjugate issue.
     
  8. May 2, 2016 #7

    TSny

    User Avatar
    Homework Helper
    Gold Member

    Consider the ratio of the magnitude of the centrifugal term to the magnitude of the Coriolis term for typical numbers.

    Note mfb's comment in post 4. The complex conjugate term is not written correctly. There's been a mishandling of a factor of i.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted