Inertial frame S' moves at a speed of 0.6c with respect to frame S. Further, x = x' = 0 at t = t' = 0. Two events are recorded. In frame S, event 1 occurs at the origin at t = 0 and event 2 occurs on the x-axis at x = 3000m at t = 4*10-6 s. According to observer S', what is the time of (a) event 1 and (b) event 2? (c) Do the two observers see the two events in the same sequence or the reverse sequence?
Standard Lorentz Transformation Equations.
The Attempt at a Solution
x1 = 0, x2 = 3000m, t1 = 0, t2 = 4*10-6 s
x1' = 0, x2' = 2850m, t1' = 0, t2' = -2.5*10-6s
Based on the question, x2' is some distance away and event 1 occurs at t = 0 in frame S'.
1) It requires some time for light to reach event 2 in S'
2) Event 1 ALREADY occurs at t = 0
Then shouldn't event 1 occur first regardless of whatever speed you are travelling?
How does the concept of 'negative' time come into play here? I'm finding this very, very strange..