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## Homework Statement

Inertial frame S' moves at a speed of 0.6c with respect to frame S. Further, x = x' = 0 at t = t' = 0. Two events are recorded. In frame S, event 1 occurs at the origin at t = 0 and event 2 occurs on the x-axis at x = 3000m at t = 4*10

^{-6}s. According to observer S', what is the time of (a) event 1 and (b) event 2? (c) Do the two observers see the two events in the same sequence or the reverse sequence?

## Homework Equations

Standard Lorentz Transformation Equations.

## The Attempt at a Solution

x

_{1}= 0, x

_{2}= 3000m, t

_{1}= 0, t

_{2}= 4*10

^{-6}s

x

_{1}' = 0, x

_{2}' = 2850m, t

_{1}' = 0, t

_{2}' = -2.5*10

^{-6}s

Based on the question, x

_{2}' is some distance away and event 1 occurs at t = 0 in frame S'.

1) It requires some time for light to reach event 2 in S'

2) Event 1 ALREADY occurs at t = 0

Then shouldn't event 1 occur first regardless of whatever speed you are travelling?

How does the concept of 'negative' time come into play here? I'm finding this very, very strange..