Grade 10 Physics: Displacement of Speedboat

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To calculate the displacement of the speedboat, the problem should be approached in two parts: first, the displacement during the initial 90 seconds at a constant speed of 6.0 m/s, and second, the displacement during the subsequent 5 seconds while accelerating at 2.0 m/s². The formula Delta D = V1 * Delta T + 1/2 * A * (Delta T)² is appropriate for the second part, where 'a' represents vector acceleration. The total time for the calculation should not be combined; instead, the displacements from each segment must be calculated separately and then summed. This method ensures accurate results by accounting for the different conditions of motion.
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Homework Statement


ok here's the question

A speed boat travels at 6.0 m/s [E] for 90s and then accelerates uniformly at 2.0 m/s² [E] for 5.0s. Caculate the displacement of the speedboat


Homework Equations


is this the formula i am suppose to use for this question?

Delta D= V1*Delta T+1/2*A(Delta T)²

note that the a in that formula is suppose to be vector acceleration.

for the time do i just add up 90 seconds and 5 seconds?
 
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HelloMotto said:

Homework Statement


ok here's the question

A speed boat travels at 6.0 m/s [E] for 90s and then accelerates uniformly at 2.0 m/s² [E] for 5.0s. Caculate the displacement of the speedboat


Homework Equations


is this the formula i am suppose to use for this question?

Delta D= V1*Delta T+1/2*A(Delta T)²

note that the a in that formula is suppose to be vector acceleration.

for the time do i just add up 90 seconds and 5 seconds?
No, you should look at the question in 2 parts, the first being the displacement over the first 90 seconds at constant speed (no acceleration), and the second part being the displacement over the next 5 seconds at the given acceleration and initial speed. Then add 'em up. You can't do it all at once, since the acceleartions are different over the noted time periods.
 
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