Gradient of a dot product identity proof?

Libohove90
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Gradient of a dot product identity proof?

Homework Statement


I have been given a E&M homework assignment to prove all the vector identities in the front cover of Griffith's E&M textbook. I have trouble proving:

(1) ∇(A[itex]\bullet[/itex]B) = A×(∇×B)+B×(∇×A)+(A[itex]\bullet[/itex]∇)B+(B[itex]\bullet[/itex]∇)A

Homework Equations


(2) A×(B×C) = B(A[itex]\bullet[/itex]C)-C(A[itex]\bullet[/itex]B)


The Attempt at a Solution


I applied the identity in equation (2) to the first two terms on the right hand side of equation (1), and that allowed me to cancel out 4 terms. Yet, I end up with:

∇(A[itex]\bullet[/itex]B) = ∇(A[itex]\bullet[/itex]B)+∇(B[itex]\bullet[/itex]A)

...which I know cannot be correct. How can I prove this identity in a relatively straightforward way? I have seen other pages asking this yet they all involved the use of Levi-Cevita symbols and the Kronecker Delta, which I am trying not to use because we haven't learned them. I would gladly appreciate anyone's effort to help me out.
 
on Phys.org


The only sensible way I can see is to do it by hand for let's say the <x> component in both sides and show they are the same.
 


I was hoping I can get around the long calculations lol
 


You have to be careful with the ∇ operator in vector identities, as it is not commutative. I think this caused the problem here.
The long calculation will work, and it is sufficient to consider one component.
 


Libohove90 said:
I was hoping I can get around the long calculations lol
I know you wanted avoid them, but it's definitely worth learning about the Kronecker delta and Levi-Civita symbol. Using them makes verifying the identity much easier.
 

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